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13280651 is a prime number
BaseRepresentation
bin110010101010…
…010110001011
3220222201121222
4302222112023
511344440101
61152352255
7220612046
oct62522613
926881558
1013280651
117550a4a
12454568b
13299cb97
141a99c5d
15127501b
hexcaa58b

13280651 has 2 divisors, whose sum is σ = 13280652. Its totient is φ = 13280650.

The previous prime is 13280647. The next prime is 13280653. The reversal of 13280651 is 15608231.

13280651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (15608231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13280651 - 22 = 13280647 is a prime.

Together with 13280653, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13280651.

It is not a weakly prime, because it can be changed into another prime (13280653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6640325 + 6640326.

It is an arithmetic number, because the mean of its divisors is an integer number (6640326).

Almost surely, 213280651 is an apocalyptic number.

13280651 is a deficient number, since it is larger than the sum of its proper divisors (1).

13280651 is an equidigital number, since it uses as much as digits as its factorization.

13280651 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 13280651 is about 3644.2627512297. The cubic root of 13280651 is about 236.8134990003.

Adding to 13280651 its reverse (15608231), we get a palindrome (28888882).

It can be divided in two parts, 13280 and 651, that added together give a palindrome (13931).

The spelling of 13280651 in words is "thirteen million, two hundred eighty thousand, six hundred fifty-one".