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1328255034000 = 243536710930313
BaseRepresentation
bin10011010101000010001…
…010110110001010010000
311200222110101011220020220
4103111002022312022100
5133230231242042000
62454105243033040
7164651253334656
oct23250212661220
94628411156226
101328255034000
11472345380464
12195511b0b780
139833bacac7b
1448405d64dd6
152483e7671a0
hex135422b6290

1328255034000 has 320 divisors, whose sum is σ = 4386227239680. Its totient is φ = 345702297600.

The previous prime is 1328255033983. The next prime is 1328255034049. The reversal of 1328255034000 is 4305528231.

It is a super-2 number, since 2×13282550340002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 43802844 + ... + 43833156.

It is an arithmetic number, because the mean of its divisors is an integer number (13706960124).

Almost surely, 21328255034000 is an apocalyptic number.

1328255034000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1328255034000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2193113619840).

1328255034000 is an abundant number, since it is smaller than the sum of its proper divisors (3057972205680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1328255034000 is a wasteful number, since it uses less digits than its factorization.

1328255034000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30515 (or 30499 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

The spelling of 1328255034000 in words is "one trillion, three hundred twenty-eight billion, two hundred fifty-five million, thirty-four thousand".