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13283075651 is a prime number
BaseRepresentation
bin11000101111011101…
…11010011001000011
31021021201110011020212
430113232322121003
5204200431410101
610034022224335
7650111165036
oct142756723103
937251404225
1013283075651
1156a6a4a37a
1226a85850ab
131338c252a1
149001b501d
1552b21b1bb
hex317bba643

13283075651 has 2 divisors, whose sum is σ = 13283075652. Its totient is φ = 13283075650.

The previous prime is 13283075599. The next prime is 13283075653. The reversal of 13283075651 is 15657038231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13283075651 - 230 = 12209333827 is a prime.

It is a Sophie Germain prime.

Together with 13283075653, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13283075599 and 13283075608.

It is not a weakly prime, because it can be changed into another prime (13283075653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6641537825 + 6641537826.

It is an arithmetic number, because the mean of its divisors is an integer number (6641537826).

Almost surely, 213283075651 is an apocalyptic number.

13283075651 is a deficient number, since it is larger than the sum of its proper divisors (1).

13283075651 is an equidigital number, since it uses as much as digits as its factorization.

13283075651 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

The spelling of 13283075651 in words is "thirteen billion, two hundred eighty-three million, seventy-five thousand, six hundred fifty-one".