Base | Representation |
---|---|
bin | 11110001100111111000000… |
… | …100011000001010011110111 |
3 | 122102022202221211022210212222 |
4 | 132030333000203001103313 |
5 | 114402321341044004041 |
6 | 1150302541343432555 |
7 | 36656626343056565 |
oct | 3614770043012367 |
9 | 572282854283788 |
10 | 132833683969271 |
11 | 393634a36a743a |
12 | 12a94083bb575b |
13 | 591721645b08c |
14 | 24b32827c8a35 |
15 | 1055497add74b |
hex | 78cfc08c14f7 |
132833683969271 has 2 divisors, whose sum is σ = 132833683969272. Its totient is φ = 132833683969270.
The previous prime is 132833683969247. The next prime is 132833683969279. The reversal of 132833683969271 is 172969386338231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132833683969271 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132833683969195 and 132833683969204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132833683969279) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66416841984635 + 66416841984636.
It is an arithmetic number, because the mean of its divisors is an integer number (66416841984636).
Almost surely, 2132833683969271 is an apocalyptic number.
132833683969271 is a deficient number, since it is larger than the sum of its proper divisors (1).
132833683969271 is an equidigital number, since it uses as much as digits as its factorization.
132833683969271 is an evil number, because the sum of its binary digits is even.
The product of its digits is 423263232, while the sum is 71.
The spelling of 132833683969271 in words is "one hundred thirty-two trillion, eight hundred thirty-three billion, six hundred eighty-three million, nine hundred sixty-nine thousand, two hundred seventy-one".
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