Base | Representation |
---|---|
bin | 10011010101101011100… |
… | …011110111010111100111 |
3 | 11201001020202212022110101 |
4 | 103111223203313113213 |
5 | 133233142030132112 |
6 | 2454302211004531 |
7 | 165004415004634 |
oct | 23255343672747 |
9 | 4631222768411 |
10 | 1328949458407 |
11 | 47267136182a |
12 | 195686599747 |
13 | 9841c93759c |
14 | 4847028b18b |
15 | 248806d7757 |
hex | 1356b8f75e7 |
1328949458407 has 2 divisors, whose sum is σ = 1328949458408. Its totient is φ = 1328949458406.
The previous prime is 1328949458393. The next prime is 1328949458413. The reversal of 1328949458407 is 7048549498231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1328949458407 - 219 = 1328948934119 is a prime.
It is a super-2 number, since 2×13289494584072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1328949458477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 664474729203 + 664474729204.
It is an arithmetic number, because the mean of its divisors is an integer number (664474729204).
Almost surely, 21328949458407 is an apocalyptic number.
1328949458407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1328949458407 is an equidigital number, since it uses as much as digits as its factorization.
1328949458407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69672960, while the sum is 64.
The spelling of 1328949458407 in words is "one trillion, three hundred twenty-eight billion, nine hundred forty-nine million, four hundred fifty-eight thousand, four hundred seven".
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