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1329138411037 is a prime number
BaseRepresentation
bin10011010101110110110…
…100101010011000011101
311201001201221102002201221
4103111312310222120131
5133234033413123122
62454333040533341
7165012201041143
oct23256664523035
94631657362657
101329138411037
11472758a89728
12195719921251
139844cb24388
144848b3d5593
15248920ad6c7
hex13576d2a61d

1329138411037 has 2 divisors, whose sum is σ = 1329138411038. Its totient is φ = 1329138411036.

The previous prime is 1329138411023. The next prime is 1329138411049. The reversal of 1329138411037 is 7301148319231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1061217263716 + 267921147321 = 1030154^2 + 517611^2 .

It is a cyclic number.

It is not a de Polignac number, because 1329138411037 - 211 = 1329138408989 is a prime.

It is a super-2 number, since 2×13291384110372 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1329138410984 and 1329138411002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1329138411077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 664569205518 + 664569205519.

It is an arithmetic number, because the mean of its divisors is an integer number (664569205519).

Almost surely, 21329138411037 is an apocalyptic number.

It is an amenable number.

1329138411037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1329138411037 is an equidigital number, since it uses as much as digits as its factorization.

1329138411037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864, while the sum is 43.

The spelling of 1329138411037 in words is "one trillion, three hundred twenty-nine billion, one hundred thirty-eight million, four hundred eleven thousand, thirty-seven".