Base | Representation |
---|---|
bin | 111101111001111100… |
… | …0000111010001111011 |
3 | 110201010212011210211221 |
4 | 1323303320013101323 |
5 | 4134230242423001 |
6 | 141023322132511 |
7 | 12414251250415 |
oct | 1736370072173 |
9 | 421125153757 |
10 | 132940592251 |
11 | 5141a553665 |
12 | 21921651137 |
13 | c6c818884c |
14 | 6611c499b5 |
15 | 36d10c01a1 |
hex | 1ef3e0747b |
132940592251 has 2 divisors, whose sum is σ = 132940592252. Its totient is φ = 132940592250.
The previous prime is 132940592207. The next prime is 132940592303. The reversal of 132940592251 is 152295049231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132940592251 - 29 = 132940591739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132940592198 and 132940592207.
It is not a weakly prime, because it can be changed into another prime (132940592201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66470296125 + 66470296126.
It is an arithmetic number, because the mean of its divisors is an integer number (66470296126).
Almost surely, 2132940592251 is an apocalyptic number.
132940592251 is a deficient number, since it is larger than the sum of its proper divisors (1).
132940592251 is an equidigital number, since it uses as much as digits as its factorization.
132940592251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 43.
The spelling of 132940592251 in words is "one hundred thirty-two billion, nine hundred forty million, five hundred ninety-two thousand, two hundred fifty-one".
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