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13295354053 = 122411086133
BaseRepresentation
bin11000110000111011…
…10000000011000101
31021022120112222001111
430120131300003011
5204212102312203
610035141325021
7650320434112
oct143035600305
937276488044
1013295354053
115702976313
1226b0706771
13133b633c07
14901a8d909
1552c34426d
hex3187700c5

13295354053 has 4 divisors (see below), whose sum is σ = 13296452428. Its totient is φ = 13294255680.

The previous prime is 13295354047. The next prime is 13295354057. The reversal of 13295354053 is 35045359231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 35045359231 = 51896753779.

It can be written as a sum of positive squares in 2 ways, for example, as 8386530084 + 4908823969 = 91578^2 + 70063^2 .

It is a cyclic number.

It is not a de Polignac number, because 13295354053 - 29 = 13295353541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13295353997 and 13295354015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13295354057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530826 + ... + 555307.

It is an arithmetic number, because the mean of its divisors is an integer number (3324113107).

Almost surely, 213295354053 is an apocalyptic number.

It is an amenable number.

13295354053 is a deficient number, since it is larger than the sum of its proper divisors (1098375).

13295354053 is a wasteful number, since it uses less digits than its factorization.

13295354053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1098374.

The product of its (nonzero) digits is 243000, while the sum is 40.

The spelling of 13295354053 in words is "thirteen billion, two hundred ninety-five million, three hundred fifty-four thousand, fifty-three".

Divisors: 1 12241 1086133 13295354053