Base | Representation |
---|---|
bin | 11000110001011110… |
… | …11110010101101111 |
3 | 1021022220022000020201 |
4 | 30120233132111233 |
5 | 204214300000421 |
6 | 10035425054331 |
7 | 650405064346 |
oct | 143057362557 |
9 | 37286260221 |
10 | 13300000111 |
11 | 5705559a32 |
12 | 26b21873a7 |
13 | 133c59c868 |
14 | 90253cb5d |
15 | 52c960b91 |
hex | 318bde56f |
13300000111 has 4 divisors (see below), whose sum is σ = 13300526232. Its totient is φ = 13299473992.
The previous prime is 13300000093. The next prime is 13300000123. The reversal of 13300000111 is 11100000331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13300000111 - 29 = 13299999599 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300000151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223120 + ... + 276373.
It is an arithmetic number, because the mean of its divisors is an integer number (3325131558).
Almost surely, 213300000111 is an apocalyptic number.
13300000111 is a deficient number, since it is larger than the sum of its proper divisors (526121).
13300000111 is an equidigital number, since it uses as much as digits as its factorization.
13300000111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 526120.
The product of its (nonzero) digits is 9, while the sum is 10.
Adding to 13300000111 its reverse (11100000331), we get a palindrome (24400000442).
The spelling of 13300000111 in words is "thirteen billion, three hundred million, one hundred eleven", and thus it is an aban number.
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