13300010551 has 4 divisors (see below), whose sum is σ = 13384724152. Its totient is φ = 13215296952.

The previous prime is 13300010519. The next prime is 13300010557. The reversal of 13300010551 is 15501000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13300010551 - 2⁵ = 13300010519 is a prime.

It is a super-2 number, since 2×13300010551² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300010557) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42356565 + ... + 42356878.

It is an arithmetic number, because the mean of its divisors is an integer number (3346181038).

Almost surely, 2^13300010551 is an apocalyptic number.

13300010551 is a deficient number, since it is larger than the sum of its proper divisors (84713601).

13300010551 is an equidigital number, since it uses as much as digits as its factorization.

13300010551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84713600.

The product of its (nonzero) digits is 225, while the sum is 19.

Adding to 13300010551 its reverse (15501000331), we get a palindrome (28801010882).

The spelling of 13300010551 in words is "thirteen billion, three hundred million, ten thousand, five hundred fifty-one".