13300012147 has 2 divisors, whose sum is σ = 13300012148. Its totient is φ = 13300012146.

The previous prime is 13300012127. The next prime is 13300012157. The reversal of 13300012147 is 74121000331.

13300012147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13300012147 - 2¹¹ = 13300010099 is a prime.

It is a super-2 number, since 2×13300012147² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13300012127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650006073 + 6650006074.

It is an arithmetic number, because the mean of its divisors is an integer number (6650006074).

Almost surely, 2^13300012147 is an apocalyptic number.

13300012147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300012147 is an equidigital number, since it uses as much as digits as its factorization.

13300012147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 22.

Adding to 13300012147 its reverse (74121000331), we get a palindrome (87421012478).

The spelling of 13300012147 in words is "thirteen billion, three hundred million, twelve thousand, one hundred forty-seven".