Base | Representation |
---|---|
bin | 1100000110001010011010… |
… | …0100000001101000111101 |
3 | 1202002110122210021200222021 |
4 | 3001202212210001220331 |
5 | 3220401411340211143 |
6 | 44141535224520141 |
7 | 2541615503663464 |
oct | 301424644015075 |
9 | 52073583250867 |
10 | 13300013210173 |
11 | 426855a7a9a98 |
12 | 15a976b620051 |
13 | 756255460aa1 |
14 | 33da1cc059db |
15 | 180e6d0a4ced |
hex | c18a6901a3d |
13300013210173 has 2 divisors, whose sum is σ = 13300013210174. Its totient is φ = 13300013210172.
The previous prime is 13300013210161. The next prime is 13300013210201. The reversal of 13300013210173 is 37101231000331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7923425560164 + 5376587650009 = 2814858^2 + 2318747^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300013210173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300013210273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650006605086 + 6650006605087.
It is an arithmetic number, because the mean of its divisors is an integer number (6650006605087).
Almost surely, 213300013210173 is an apocalyptic number.
It is an amenable number.
13300013210173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300013210173 is an equidigital number, since it uses as much as digits as its factorization.
13300013210173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
The spelling of 13300013210173 in words is "thirteen trillion, three hundred billion, thirteen million, two hundred ten thousand, one hundred seventy-three".
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