133000411 has 4 divisors (see below), whose sum is σ = 133029000. Its totient is φ = 132971824.

The previous prime is 133000403. The next prime is 133000423. The reversal of 133000411 is 114000331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 114000331 = 59 ⋅1932209.

It is a cyclic number.

It is not a de Polignac number, because 133000411 - 2³ = 133000403 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133000391 and 133000400.

It is not an unprimeable number, because it can be changed into a prime (133000481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5521 + ... + 17218.

It is an arithmetic number, because the mean of its divisors is an integer number (33257250).

Almost surely, 2^133000411 is an apocalyptic number.

133000411 is a deficient number, since it is larger than the sum of its proper divisors (28589).

133000411 is an equidigital number, since it uses as much as digits as its factorization.

133000411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28588.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 133000411 is about 11532.5804137669. The cubic root of 133000411 is about 510.4473979983.

Adding to 133000411 its reverse (114000331), we get a palindrome (247000742).

The spelling of 133000411 in words is "one hundred thirty-three million, four hundred eleven", and thus it is an aban number.