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13300099999931 is a prime number
BaseRepresentation
bin1100000110001010101110…
…1111000110100010111011
31202002110212211121002010202
43001202223233012202323
53220402101044444211
644141552005032415
72541620606456033
oct301425357064273
952073784532122
1013300099999931
1142685a4798468
1215a97946b570b
1375626a42a784
1433da2a5588c3
15180e759ea53b
hexc18abbc68bb

13300099999931 has 2 divisors, whose sum is σ = 13300099999932. Its totient is φ = 13300099999930.

The previous prime is 13300099999913. The next prime is 13300099999937. The reversal of 13300099999931 is 13999999000331.

Together with previous prime (13300099999913) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300099999931 is a prime.

It is a super-2 number, since 2×133000999999312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13300099999937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650049999965 + 6650049999966.

It is an arithmetic number, because the mean of its divisors is an integer number (6650049999966).

Almost surely, 213300099999931 is an apocalyptic number.

13300099999931 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300099999931 is an equidigital number, since it uses as much as digits as its factorization.

13300099999931 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14348907, while the sum is 65.

The spelling of 13300099999931 in words is "thirteen trillion, three hundred billion, ninety-nine million, nine hundred ninety-nine thousand, nine hundred thirty-one".