13300100000041 has 2 divisors, whose sum is σ = 13300100000042. Its totient is φ = 13300100000040.

The previous prime is 13300100000029. The next prime is 13300100000051. The reversal of 13300100000041 is 14000000100331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9317664675225 + 3982435324816 = 3052485^2 + 1995604^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300100000041 - 2⁷ = 13300099999913 is a prime.

It is a super-2 number, since 2×13300100000041² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13300099999967 and 13300100000030.

It is not a weakly prime, because it can be changed into another prime (13300100000051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650050000020 + 6650050000021.

It is an arithmetic number, because the mean of its divisors is an integer number (6650050000021).

Almost surely, 2^{13300100000041} is an apocalyptic number.

It is an amenable number.

13300100000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300100000041 is an equidigital number, since it uses as much as digits as its factorization.

13300100000041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13300100000041 its reverse (14000000100331), we get a palindrome (27300100100372).

The spelling of 13300100000041 in words is "thirteen trillion, three hundred billion, one hundred million, forty-one", and thus it is an aban number.