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13300100323020 = 2235572113495309
BaseRepresentation
bin1100000110001010101111…
…0000010101011011001100
31202002110212212012111100000
43001202223300111123030
53220402101140314040
644141552020004300
72541620612303010
oct301425360253314
952073785174300
1013300100323020
1142685a4999185
1215a9794830690
1375626a511854
1433da2a600540
15180e75a61130
hexc18abc156cc

13300100323020 has 576 divisors, whose sum is σ = 48188020608000. Its totient is φ = 3016377584640.

The previous prime is 13300100323007. The next prime is 13300100323043. The reversal of 13300100323020 is 2032300100331.

13300100323020 is a `hidden beast` number, since 1 + 330 + 0 + 1 + 0 + 0 + 32 + 302 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13300100322984 and 13300100323002.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 2505196126 + ... + 2505201434.

It is an arithmetic number, because the mean of its divisors is an integer number (83659758000).

Almost surely, 213300100323020 is an apocalyptic number.

13300100323020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13300100323020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24094010304000).

13300100323020 is an abundant number, since it is smaller than the sum of its proper divisors (34887920284980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300100323020 is a wasteful number, since it uses less digits than its factorization.

13300100323020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5900 (or 5886 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 18.

Adding to 13300100323020 its reverse (2032300100331), we get a palindrome (15332400423351).

The spelling of 13300100323020 in words is "thirteen trillion, three hundred billion, one hundred million, three hundred twenty-three thousand, twenty".