Base | Representation |
---|---|
bin | 1100000110001010101111… |
… | …1011011011101001110001 |
3 | 1202002110220001200021212012 |
4 | 3001202223323123221301 |
5 | 3220402102411411423 |
6 | 44141552202212305 |
7 | 2541620646110225 |
oct | 301425373335161 |
9 | 52073801607765 |
10 | 13300103232113 |
11 | 42685a65a5895 |
12 | 15a97957b4095 |
13 | 75626acbc9c9 |
14 | 33da2ab5a785 |
15 | 180e75e38078 |
hex | c18abedba71 |
13300103232113 has 2 divisors, whose sum is σ = 13300103232114. Its totient is φ = 13300103232112.
The previous prime is 13300103232089. The next prime is 13300103232127. The reversal of 13300103232113 is 31123230100331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12980542533904 + 319560698209 = 3602852^2 + 565297^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300103232113 - 236 = 13231383755377 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300103232173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650051616056 + 6650051616057.
It is an arithmetic number, because the mean of its divisors is an integer number (6650051616057).
Almost surely, 213300103232113 is an apocalyptic number.
It is an amenable number.
13300103232113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300103232113 is an equidigital number, since it uses as much as digits as its factorization.
13300103232113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 13300103232113 its reverse (31123230100331), we get a palindrome (44423333332444).
The spelling of 13300103232113 in words is "thirteen trillion, three hundred billion, one hundred three million, two hundred thirty-two thousand, one hundred thirteen".
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