Base | Representation |
---|---|
bin | 111101111011101111… |
… | …0111110101001001111 |
3 | 110201022002001112112102 |
4 | 1323313132332221033 |
5 | 4134341241042033 |
6 | 141033323225315 |
7 | 12415614541304 |
oct | 1736736765117 |
9 | 421262045472 |
10 | 133001112143 |
11 | 5145072a0a9 |
12 | 2193997823b |
13 | c707888333 |
14 | 6619cc10ab |
15 | 36d6576de8 |
hex | 1ef77bea4f |
133001112143 has 2 divisors, whose sum is σ = 133001112144. Its totient is φ = 133001112142.
The previous prime is 133001112133. The next prime is 133001112199. The reversal of 133001112143 is 341211100331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133001112143 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133001112133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500556071 + 66500556072.
It is an arithmetic number, because the mean of its divisors is an integer number (66500556072).
Almost surely, 2133001112143 is an apocalyptic number.
133001112143 is a deficient number, since it is larger than the sum of its proper divisors (1).
133001112143 is an equidigital number, since it uses as much as digits as its factorization.
133001112143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 133001112143 its reverse (341211100331), we get a palindrome (474212212474).
The spelling of 133001112143 in words is "one hundred thirty-three billion, one million, one hundred twelve thousand, one hundred forty-three".
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