Base | Representation |
---|---|
bin | 11000110001011111… |
… | …11001011111001111 |
3 | 1021022220111122210020 |
4 | 30120233321133033 |
5 | 204214312030221 |
6 | 10035431313223 |
7 | 650406036504 |
oct | 143057713717 |
9 | 37286448706 |
10 | 13300111311 |
11 | 5705625533 |
12 | 26b221b813 |
13 | 133c60b366 |
14 | 90256b4ab |
15 | 52c983ac6 |
hex | 318bf97cf |
13300111311 has 4 divisors (see below), whose sum is σ = 17733481752. Its totient is φ = 8866740872.
The previous prime is 13300111303. The next prime is 13300111339. The reversal of 13300111311 is 11311100331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13300111311 - 23 = 13300111303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300111351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2216685216 + ... + 2216685221.
It is an arithmetic number, because the mean of its divisors is an integer number (4433370438).
Almost surely, 213300111311 is an apocalyptic number.
13300111311 is a deficient number, since it is larger than the sum of its proper divisors (4433370441).
13300111311 is an equidigital number, since it uses as much as digits as its factorization.
13300111311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4433370440.
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 13300111311 its reverse (11311100331), we get a palindrome (24611211642).
The spelling of 13300111311 in words is "thirteen billion, three hundred million, one hundred eleven thousand, three hundred eleven".
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