Base | Representation |
---|---|
bin | 1100000110001010110001… |
… | …1100111011001111010011 |
3 | 1202002110220200012100221012 |
4 | 3001202230130323033103 |
5 | 3220402112133342433 |
6 | 44141553114321135 |
7 | 2541621113536250 |
oct | 301425434731723 |
9 | 52073820170835 |
10 | 13300112012243 |
11 | 42686005524a1 |
12 | 15a97987291ab |
13 | 75626ca75254 |
14 | 33da2bda4427 |
15 | 180e76abe848 |
hex | c18ac73b3d3 |
13300112012243 has 4 divisors (see below), whose sum is σ = 15200128014000. Its totient is φ = 11400096010488.
The previous prime is 13300112012197. The next prime is 13300112012251. The reversal of 13300112012243 is 34221021100331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300112012243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13300112012743) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950008000868 + ... + 950008000881.
It is an arithmetic number, because the mean of its divisors is an integer number (3800032003500).
Almost surely, 213300112012243 is an apocalyptic number.
13300112012243 is a deficient number, since it is larger than the sum of its proper divisors (1900016001757).
13300112012243 is an equidigital number, since it uses as much as digits as its factorization.
13300112012243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1900016001756.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13300112012243 its reverse (34221021100331), we get a palindrome (47521133112574).
The spelling of 13300112012243 in words is "thirteen trillion, three hundred billion, one hundred twelve million, twelve thousand, two hundred forty-three".
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