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13300112012243 = 71900016001749
BaseRepresentation
bin1100000110001010110001…
…1100111011001111010011
31202002110220200012100221012
43001202230130323033103
53220402112133342433
644141553114321135
72541621113536250
oct301425434731723
952073820170835
1013300112012243
1142686005524a1
1215a97987291ab
1375626ca75254
1433da2bda4427
15180e76abe848
hexc18ac73b3d3

13300112012243 has 4 divisors (see below), whose sum is σ = 15200128014000. Its totient is φ = 11400096010488.

The previous prime is 13300112012197. The next prime is 13300112012251. The reversal of 13300112012243 is 34221021100331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300112012243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300112012743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 950008000868 + ... + 950008000881.

It is an arithmetic number, because the mean of its divisors is an integer number (3800032003500).

Almost surely, 213300112012243 is an apocalyptic number.

13300112012243 is a deficient number, since it is larger than the sum of its proper divisors (1900016001757).

13300112012243 is an equidigital number, since it uses as much as digits as its factorization.

13300112012243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1900016001756.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13300112012243 its reverse (34221021100331), we get a palindrome (47521133112574).

The spelling of 13300112012243 in words is "thirteen trillion, three hundred billion, one hundred twelve million, twelve thousand, two hundred forty-three".

Divisors: 1 7 1900016001749 13300112012243