1330012122301 has 4 divisors (see below), whose sum is σ = 1330037285472. Its totient is φ = 1329986959132.

The previous prime is 1330012122287. The next prime is 1330012122371. The reversal of 1330012122301 is 1032212100331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330012122301 - 2⁵ = 1330012122269 is a prime.

It is a super-2 number, since 2×1330012122301² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330012122371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12502135 + ... + 12608068.

It is an arithmetic number, because the mean of its divisors is an integer number (332509321368).

Almost surely, 2^{1330012122301} is an apocalyptic number.

It is an amenable number.

1330012122301 is a deficient number, since it is larger than the sum of its proper divisors (25163171).

1330012122301 is an equidigital number, since it uses as much as digits as its factorization.

1330012122301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25163170.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1330012122301 its reverse (1032212100331), we get a palindrome (2362224222632).

The spelling of 1330012122301 in words is "one trillion, three hundred thirty billion, twelve million, one hundred twenty-two thousand, three hundred one".