Base | Representation |
---|---|
bin | 10011010110101010111… |
… | …001111001110011010101 |
3 | 11201010222211121012001122 |
4 | 103112222321321303111 |
5 | 133242331110401044 |
6 | 2454555453133325 |
7 | 165042641112233 |
oct | 23265271716325 |
9 | 4633884535048 |
10 | 1330012200149 |
11 | 473067239396 |
12 | 19592248a245 |
13 | 9855bb71659 |
14 | 4853148b953 |
15 | 248e3b5ddee |
hex | 135aae79cd5 |
1330012200149 has 2 divisors, whose sum is σ = 1330012200150. Its totient is φ = 1330012200148.
The previous prime is 1330012200103. The next prime is 1330012200161. The reversal of 1330012200149 is 9410022100331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1323231501124 + 6780699025 = 1150318^2 + 82345^2 .
It is an emirp because it is prime and its reverse (9410022100331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330012200149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330012200199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665006100074 + 665006100075.
It is an arithmetic number, because the mean of its divisors is an integer number (665006100075).
Almost surely, 21330012200149 is an apocalyptic number.
It is an amenable number.
1330012200149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330012200149 is an equidigital number, since it uses as much as digits as its factorization.
1330012200149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 26.
The spelling of 1330012200149 in words is "one trillion, three hundred thirty billion, twelve million, two hundred thousand, one hundred forty-nine".
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