133001223100111 has 4 divisors (see below), whose sum is σ = 133001320009824. Its totient is φ = 133001126190400.

The previous prime is 133001223100099. The next prime is 133001223100177. The reversal of 133001223100111 is 111001322100331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133001223100111 - 2⁵ = 133001223100079 is a prime.

It is a super-2 number, since 2×133001223100111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133001223500111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46366210 + ... + 49151071.

It is an arithmetic number, because the mean of its divisors is an integer number (33250330002456).

Almost surely, 2^{133001223100111} is an apocalyptic number.

133001223100111 is a deficient number, since it is larger than the sum of its proper divisors (96909713).

133001223100111 is an equidigital number, since it uses as much as digits as its factorization.

133001223100111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96909712.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 133001223100111 its reverse (111001322100331), we get a palindrome (244002545200442).

The spelling of 133001223100111 in words is "one hundred thirty-three trillion, one billion, two hundred twenty-three million, one hundred thousand, one hundred eleven".