Base | Representation |
---|---|
bin | 1100000110001010111000… |
… | …0111101101001100001111 |
3 | 1202002110222121212111120001 |
4 | 3001202232013231030033 |
5 | 3220402141320112421 |
6 | 44141555554305131 |
7 | 2541621603502222 |
oct | 301425607551417 |
9 | 52073877774501 |
10 | 13300140004111 |
11 | 4268615331174 |
12 | 15a97a5b881a7 |
13 | 7562757c619c |
14 | 33da319ad5b9 |
15 | 180e7929d691 |
hex | c18ae1ed30f |
13300140004111 has 2 divisors, whose sum is σ = 13300140004112. Its totient is φ = 13300140004110.
The previous prime is 13300140004043. The next prime is 13300140004157. The reversal of 13300140004111 is 11140004100331.
13300140004111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13300140004111 - 227 = 13300005786383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300140004511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650070002055 + 6650070002056.
It is an arithmetic number, because the mean of its divisors is an integer number (6650070002056).
Almost surely, 213300140004111 is an apocalyptic number.
13300140004111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300140004111 is an equidigital number, since it uses as much as digits as its factorization.
13300140004111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 13300140004111 its reverse (11140004100331), we get a palindrome (24440144104442).
The spelling of 13300140004111 in words is "thirteen trillion, three hundred billion, one hundred forty million, four thousand, one hundred eleven".
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