13300154351051 has 2 divisors, whose sum is σ = 13300154351052. Its totient is φ = 13300154351050.

The previous prime is 13300154351021. The next prime is 13300154351053. The reversal of 13300154351051 is 15015345100331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13300154351051 is a prime.

Together with 13300154351053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13300154350999 and 13300154351017.

It is not a weakly prime, because it can be changed into another prime (13300154351053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650077175525 + 6650077175526.

It is an arithmetic number, because the mean of its divisors is an integer number (6650077175526).

Almost surely, 2^{13300154351051} is an apocalyptic number.

13300154351051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300154351051 is an equidigital number, since it uses as much as digits as its factorization.

13300154351051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13500, while the sum is 32.

Adding to 13300154351051 its reverse (15015345100331), we get a palindrome (28315499451382).

The spelling of 13300154351051 in words is "thirteen trillion, three hundred billion, one hundred fifty-four million, three hundred fifty-one thousand, fifty-one".