Base | Representation |
---|---|
bin | 111101111011110001… |
… | …1001010101011111001 |
3 | 110201022011010022120022 |
4 | 1323313203022223321 |
5 | 4134342031210131 |
6 | 141033402540225 |
7 | 12415630063211 |
oct | 1736743125371 |
9 | 421264108508 |
10 | 133002210041 |
11 | 51451309a58 |
12 | 2193a207675 |
13 | c707b80c8c |
14 | 661a0c9241 |
15 | 36d66e237b |
hex | 1ef78caaf9 |
133002210041 has 8 divisors (see below), whose sum is σ = 134701998720. Its totient is φ = 131302826928.
The previous prime is 133002210031. The next prime is 133002210049. The reversal of 133002210041 is 140012200331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133002210041 - 214 = 133002193657 is a prime.
It is a super-3 number, since 3×1330022100413 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133002210049) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 588470 + ... + 782496.
It is an arithmetic number, because the mean of its divisors is an integer number (16837749840).
Almost surely, 2133002210041 is an apocalyptic number.
It is an amenable number.
133002210041 is a deficient number, since it is larger than the sum of its proper divisors (1699788679).
133002210041 is an equidigital number, since it uses as much as digits as its factorization.
133002210041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 202783.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 133002210041 its reverse (140012200331), we get a palindrome (273014410372).
The spelling of 133002210041 in words is "one hundred thirty-three billion, two million, two hundred ten thousand, forty-one".
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