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133002213100331 = 662003200908777
BaseRepresentation
bin11110001111011011111101…
…101010101000101100101011
3122102220212221220121201010212
4132033123331222220230223
5114413102013023202311
61150512212335531335
740005043554046241
oct3617337552505453
9572825856551125
10133002213100331
1139418a15a30a43
1212b00878089b4b
13592a0937524c3
1424bb4acd82791
151059a5d245c8b
hex78f6fdaa8b2b

133002213100331 has 4 divisors (see below), whose sum is σ = 133002414671112. Its totient is φ = 133002011529552.

The previous prime is 133002213100291. The next prime is 133002213100343. The reversal of 133002213100331 is 133001312200331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133002213100331 is a prime.

It is a super-3 number, since 3×1330022131003313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133002213100297 and 133002213100306.

It is not an unprimeable number, because it can be changed into a prime (133002213100391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99792386 + ... + 101116391.

It is an arithmetic number, because the mean of its divisors is an integer number (33250603667778).

Almost surely, 2133002213100331 is an apocalyptic number.

133002213100331 is a deficient number, since it is larger than the sum of its proper divisors (201570781).

133002213100331 is an equidigital number, since it uses as much as digits as its factorization.

133002213100331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201570780.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 133002213100331 its reverse (133001312200331), we get a palindrome (266003525300662).

The spelling of 133002213100331 in words is "one hundred thirty-three trillion, two billion, two hundred thirteen million, one hundred thousand, three hundred thirty-one".

Divisors: 1 662003 200908777 133002213100331