Base | Representation |
---|---|
bin | 1100000110001011001100… |
… | …0100010110110111111011 |
3 | 1202002111012102001202110011 |
4 | 3001202303010112313323 |
5 | 3220402324042343342 |
6 | 44142012121402351 |
7 | 2541623632164565 |
oct | 301426304266773 |
9 | 52074172052404 |
10 | 13300223012347 |
11 | 4268658177517 |
12 | 15a98099393b7 |
13 | 756289a6a89b |
14 | 33da3ca1a335 |
15 | 180e816e8717 |
hex | c18b3116dfb |
13300223012347 has 2 divisors, whose sum is σ = 13300223012348. Its totient is φ = 13300223012346.
The previous prime is 13300223012249. The next prime is 13300223012353. The reversal of 13300223012347 is 74321032200331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13300223012347 - 239 = 12750467198459 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300223012357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650111506173 + 6650111506174.
It is an arithmetic number, because the mean of its divisors is an integer number (6650111506174).
Almost surely, 213300223012347 is an apocalyptic number.
13300223012347 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300223012347 is an equidigital number, since it uses as much as digits as its factorization.
13300223012347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 31.
Adding to 13300223012347 its reverse (74321032200331), we get a palindrome (87621255212678).
The spelling of 13300223012347 in words is "thirteen trillion, three hundred billion, two hundred twenty-three million, twelve thousand, three hundred forty-seven".
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