Base | Representation |
---|---|
bin | 1100000110001011001110… |
… | …0110101110100001100001 |
3 | 1202002111020001000111112012 |
4 | 3001202303212232201201 |
5 | 3220402333344201423 |
6 | 44142013042442305 |
7 | 2541624101601251 |
oct | 301426346564141 |
9 | 52074201014465 |
10 | 13300232022113 |
11 | 4268662270703 |
12 | 15a9810963395 |
13 | 75628b8a37ca |
14 | 33da3dcc3961 |
15 | 180e823c8078 |
hex | c18b39ae861 |
13300232022113 has 2 divisors, whose sum is σ = 13300232022114. Its totient is φ = 13300232022112.
The previous prime is 13300232022059. The next prime is 13300232022127. The reversal of 13300232022113 is 31122023200331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13282577053729 + 17654968384 = 3644527^2 + 132872^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13300232022113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13300232022613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650116011056 + 6650116011057.
It is an arithmetic number, because the mean of its divisors is an integer number (6650116011057).
Almost surely, 213300232022113 is an apocalyptic number.
It is an amenable number.
13300232022113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300232022113 is an equidigital number, since it uses as much as digits as its factorization.
13300232022113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13300232022113 its reverse (31122023200331), we get a palindrome (44422255222444).
The spelling of 13300232022113 in words is "thirteen trillion, three hundred billion, two hundred thirty-two million, twenty-two thousand, one hundred thirteen".
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