Base | Representation |
---|---|
bin | 1100000110001011011111… |
… | …0010111011100110000111 |
3 | 1202002111101221022112011011 |
4 | 3001202313302323212013 |
5 | 3220403004344031442 |
6 | 44142024033423051 |
7 | 2541625614320242 |
oct | 301426762734607 |
9 | 52074357275134 |
10 | 13300302330247 |
11 | 4268698a221a9 |
12 | 15a983040aa87 |
13 | 7562a031c65a |
14 | 33da49386259 |
15 | 180e88665117 |
hex | c18b7cbb987 |
13300302330247 has 2 divisors, whose sum is σ = 13300302330248. Its totient is φ = 13300302330246.
The previous prime is 13300302330191. The next prime is 13300302330269. The reversal of 13300302330247 is 74203320300331.
It is a strong prime.
It is an emirp because it is prime and its reverse (74203320300331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13300302330247 - 223 = 13300293941639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300302330277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650151165123 + 6650151165124.
It is an arithmetic number, because the mean of its divisors is an integer number (6650151165124).
Almost surely, 213300302330247 is an apocalyptic number.
13300302330247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300302330247 is an equidigital number, since it uses as much as digits as its factorization.
13300302330247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 31.
Adding to 13300302330247 its reverse (74203320300331), we get a palindrome (87503622630578).
The spelling of 13300302330247 in words is "thirteen trillion, three hundred billion, three hundred two million, three hundred thirty thousand, two hundred forty-seven".
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