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13300324013477 is a prime number
BaseRepresentation
bin1100000110001011100100…
…0101101001010110100101
31202002111110110010010221202
43001202321011221112211
53220403030421412402
644142030130252245
72541626266526534
oct301427105512645
952074413103852
1013300324013477
1142686aa192126
1215a9837727085
137562a4971c77
1433da4c1cc31b
15180e8a4e9b02
hexc18b91695a5

13300324013477 has 2 divisors, whose sum is σ = 13300324013478. Its totient is φ = 13300324013476.

The previous prime is 13300324013393. The next prime is 13300324013551. The reversal of 13300324013477 is 77431042300331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7490517608161 + 5809806405316 = 2736881^2 + 2410354^2 .

It is an emirp because it is prime and its reverse (77431042300331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300324013477 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13300324013477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300324013677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650162006738 + 6650162006739.

It is an arithmetic number, because the mean of its divisors is an integer number (6650162006739).

Almost surely, 213300324013477 is an apocalyptic number.

It is an amenable number.

13300324013477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300324013477 is an equidigital number, since it uses as much as digits as its factorization.

13300324013477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 38.

The spelling of 13300324013477 in words is "thirteen trillion, three hundred billion, three hundred twenty-four million, thirteen thousand, four hundred seventy-seven".