13300324113413 has 4 divisors (see below), whose sum is σ = 13300331413440. Its totient is φ = 13300316813388.

The previous prime is 13300324113409. The next prime is 13300324113431. The reversal of 13300324113413 is 31431142300331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13300324113413 - 2² = 13300324113409 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300324113443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1601156 + ... + 5400402.

It is an arithmetic number, because the mean of its divisors is an integer number (3325082853360).

Almost surely, 2^{13300324113413} is an apocalyptic number.

It is an amenable number.

13300324113413 is a deficient number, since it is larger than the sum of its proper divisors (7300027).

13300324113413 is an equidigital number, since it uses as much as digits as its factorization.

13300324113413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7300026.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 13300324113413 its reverse (31431142300331), we get a palindrome (44731466413744).

It can be divided in two parts, 1330032 and 4113413, that added together give a palindrome (5443445).

The spelling of 13300324113413 in words is "thirteen trillion, three hundred billion, three hundred twenty-four million, one hundred thirteen thousand, four hundred thirteen".