Base | Representation |
---|---|
bin | 1100000110001011101000… |
… | …0110011110111000010101 |
3 | 1202002111111122002122201102 |
4 | 3001202322012132320111 |
5 | 3220403044244304231 |
6 | 44142031534435445 |
7 | 2541626564146106 |
oct | 301427206367025 |
9 | 52074448078642 |
10 | 13300341009941 |
11 | 4268708840897 |
12 | 15a9841362b85 |
13 | 7562a834324b |
14 | 33da505743ad |
15 | 180e8bc55acb |
hex | c18ba19ee15 |
13300341009941 has 2 divisors, whose sum is σ = 13300341009942. Its totient is φ = 13300341009940.
The previous prime is 13300341009899. The next prime is 13300341010003. The reversal of 13300341009941 is 14990014300331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13292513892100 + 7827117841 = 3645890^2 + 88471^2 .
It is a cyclic number.
It is not a de Polignac number, because 13300341009941 - 210 = 13300341008917 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13300341009895 and 13300341009904.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300341009341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650170504970 + 6650170504971.
It is an arithmetic number, because the mean of its divisors is an integer number (6650170504971).
Almost surely, 213300341009941 is an apocalyptic number.
It is an amenable number.
13300341009941 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300341009941 is an equidigital number, since it uses as much as digits as its factorization.
13300341009941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 38.
The spelling of 13300341009941 in words is "thirteen trillion, three hundred billion, three hundred forty-one million, nine thousand, nine hundred forty-one".
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