Base | Representation |
---|---|
bin | 10011010110101100001… |
… | …101011100101110001101 |
3 | 11201011001100210212120012 |
4 | 103112230031130232031 |
5 | 133242402212214013 |
6 | 2455001554403005 |
7 | 165043325216423 |
oct | 23265415345615 |
9 | 4634040725505 |
10 | 1330034101133 |
11 | 473078637981 |
12 | 195929890465 |
13 | 9856356c10a |
14 | 4853434d113 |
15 | 248e5a381a8 |
hex | 135ac35cb8d |
1330034101133 has 16 divisors (see below), whose sum is σ = 1392246182400. Its totient is φ = 1269041437440.
The previous prime is 1330034101093. The next prime is 1330034101171. The reversal of 1330034101133 is 3311014300331.
It is a de Polignac number, because none of the positive numbers 2k-1330034101133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1330034101099 and 1330034101108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330034101633) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6275153 + ... + 6483641.
It is an arithmetic number, because the mean of its divisors is an integer number (87015386400).
Almost surely, 21330034101133 is an apocalyptic number.
It is an amenable number.
1330034101133 is a deficient number, since it is larger than the sum of its proper divisors (62212081267).
1330034101133 is a wasteful number, since it uses less digits than its factorization.
1330034101133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211412.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1330034101133 its reverse (3311014300331), we get a palindrome (4641048401464).
The spelling of 1330034101133 in words is "one trillion, three hundred thirty billion, thirty-four million, one hundred one thousand, one hundred thirty-three".
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