13300341041081 has 2 divisors, whose sum is σ = 13300341041082. Its totient is φ = 13300341041080.

The previous prime is 13300341041033. The next prime is 13300341041083. The reversal of 13300341041081 is 18014014300331.

13300341041081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9206921872681 + 4093419168400 = 3034291^2 + 2023220^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300341041081 - 2³⁴ = 13283161171897 is a prime.

It is a super-2 number, since 2×13300341041081² (a number of 27 digits) contains 22 as substring.

Together with 13300341041083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13300341041083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650170520540 + 6650170520541.

It is an arithmetic number, because the mean of its divisors is an integer number (6650170520541).

Almost surely, 2^{13300341041081} is an apocalyptic number.

It is an amenable number.

13300341041081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300341041081 is an equidigital number, since it uses as much as digits as its factorization.

13300341041081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

The spelling of 13300341041081 in words is "thirteen trillion, three hundred billion, three hundred forty-one million, forty-one thousand, eighty-one".