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13300401444403 = 14596991117987
BaseRepresentation
bin1100000110001011110110…
…1101000001011000110011
31202002111122211211001012211
43001202331231001120303
53220403210232210103
644142041534032551
72541631226632633
oct301427555013063
952074584731184
1013300401444403
114268739969127
1215a9859648757
137562b7a12b98
1433da585c66c3
15180e921e236d
hexc18bdb41633

13300401444403 has 4 divisors (see below), whose sum is σ = 13300492708360. Its totient is φ = 13300310180448.

The previous prime is 13300401444271. The next prime is 13300401444409. The reversal of 13300401444403 is 30444410400331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300401444403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13300401444409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45413025 + ... + 45704962.

It is an arithmetic number, because the mean of its divisors is an integer number (3325123177090).

Almost surely, 213300401444403 is an apocalyptic number.

13300401444403 is a deficient number, since it is larger than the sum of its proper divisors (91263957).

13300401444403 is an equidigital number, since it uses as much as digits as its factorization.

13300401444403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91263956.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13300401444403 its reverse (30444410400331), we get a palindrome (43744811844734).

The spelling of 13300401444403 in words is "thirteen trillion, three hundred billion, four hundred one million, four hundred forty-four thousand, four hundred three".

Divisors: 1 145969 91117987 13300401444403