13300402210111 has 4 divisors (see below), whose sum is σ = 13659872540152. Its totient is φ = 12940931880072.

The previous prime is 13300402210093. The next prime is 13300402210129. The reversal of 13300402210111 is 11101220400331.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13300402210093) and next prime (13300402210129).

It is a cyclic number.

It is not a de Polignac number, because 13300402210111 - 2²¹ = 13300400112959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300402210181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179735164965 + ... + 179735165038.

It is an arithmetic number, because the mean of its divisors is an integer number (3414968135038).

Almost surely, 2^{13300402210111} is an apocalyptic number.

13300402210111 is a deficient number, since it is larger than the sum of its proper divisors (359470330041).

13300402210111 is an equidigital number, since it uses as much as digits as its factorization.

13300402210111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 359470330040.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13300402210111 its reverse (11101220400331), we get a palindrome (24401622610442).

The spelling of 13300402210111 in words is "thirteen trillion, three hundred billion, four hundred two million, two hundred ten thousand, one hundred eleven".