Base | Representation |
---|---|
bin | 1100000110001011110111… |
… | …0111100011001001110111 |
3 | 1202002111200001000020212201 |
4 | 3001202331313203021313 |
5 | 3220403211434013101 |
6 | 44142042113125331 |
7 | 2541631262245561 |
oct | 301427567431167 |
9 | 52074601006781 |
10 | 13300404204151 |
11 | 4268740483609 |
12 | 15a985a559847 |
13 | 7562b846b07c |
14 | 33da58b04331 |
15 | 180e92589e01 |
hex | c18bdde3277 |
13300404204151 has 2 divisors, whose sum is σ = 13300404204152. Its totient is φ = 13300404204150.
The previous prime is 13300404204133. The next prime is 13300404204173. The reversal of 13300404204151 is 15140240400331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13300404204151 - 217 = 13300404073079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300404204751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650202102075 + 6650202102076.
It is an arithmetic number, because the mean of its divisors is an integer number (6650202102076).
Almost surely, 213300404204151 is an apocalyptic number.
13300404204151 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300404204151 is an equidigital number, since it uses as much as digits as its factorization.
13300404204151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 13300404204151 its reverse (15140240400331), we get a palindrome (28440644604482).
The spelling of 13300404204151 in words is "thirteen trillion, three hundred billion, four hundred four million, two hundred four thousand, one hundred fifty-one".
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