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13300413121213 is a prime number
BaseRepresentation
bin1100000110001011111001…
…1001100100001010111101
31202002111200122210021210021
43001202332121210022331
53220403221224334323
644142043032212141
72541631431115051
oct301427631441275
952074618707707
1013300413121213
114268745514089
1215a986153a051
137562ba270a3a
1433da59d85c61
15180e9324c05d
hexc18be6642bd

13300413121213 has 2 divisors, whose sum is σ = 13300413121214. Its totient is φ = 13300413121212.

The previous prime is 13300413121141. The next prime is 13300413121217. The reversal of 13300413121213 is 31212131400331.

13300413121213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10401573171609 + 2898839949604 = 3225147^2 + 1702598^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13300413121213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300413121217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650206560606 + 6650206560607.

It is an arithmetic number, because the mean of its divisors is an integer number (6650206560607).

Almost surely, 213300413121213 is an apocalyptic number.

It is an amenable number.

13300413121213 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300413121213 is an equidigital number, since it uses as much as digits as its factorization.

13300413121213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13300413121213 its reverse (31212131400331), we get a palindrome (44512544521544).

The spelling of 13300413121213 in words is "thirteen trillion, three hundred billion, four hundred thirteen million, one hundred twenty-one thousand, two hundred thirteen".