Base | Representation |
---|---|
bin | 1100000110001011111100… |
… | …0100101010101101110100 |
3 | 1202002111201110001100002201 |
4 | 3001202333010222231310 |
5 | 3220403232122421322 |
6 | 44142044114314244 |
7 | 2541631626134536 |
oct | 301427704525564 |
9 | 52074643040081 |
10 | 13300424420212 |
11 | 42687509311a6 |
12 | 15a9865288984 |
13 | 7562bc6c8937 |
14 | 33da5b687856 |
15 | 180e9422ed27 |
hex | c18bf12ab74 |
13300424420212 has 48 divisors (see below), whose sum is σ = 23945857447680. Its totient is φ = 6464099296800.
The previous prime is 13300424420201. The next prime is 13300424420219. The reversal of 13300424420212 is 21202442400331.
13300424420212 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13300424420219) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 208861137 + ... + 208924807.
It is an arithmetic number, because the mean of its divisors is an integer number (498872030160).
Almost surely, 213300424420212 is an apocalyptic number.
It is an amenable number.
13300424420212 is a deficient number, since it is larger than the sum of its proper divisors (10645433027468).
13300424420212 is an equidigital number, since it uses as much as digits as its factorization.
13300424420212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64817 (or 64741 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 13300424420212 its reverse (21202442400331), we get a palindrome (34502866820543).
The spelling of 13300424420212 in words is "thirteen trillion, three hundred billion, four hundred twenty-four million, four hundred twenty thousand, two hundred twelve".
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