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13300452103 = 115019115637
BaseRepresentation
bin11000110001100010…
…01100101100000111
31021022221010222021011
430120301030230013
5204214403431403
610035442503051
7650411656201
oct143061145407
937287128234
1013300452103
115705838584
1226b2364a87
13133c6ca503
14902619771
1552c9eea6d
hex318c4cb07

13300452103 has 4 divisors (see below), whose sum is σ = 13300682760. Its totient is φ = 13300221448.

The previous prime is 13300452083. The next prime is 13300452127. The reversal of 13300452103 is 30125400331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13300452103 - 217 = 13300321031 is a prime.

It is a super-2 number, since 2×133004521032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13300452703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57201 + ... + 172837.

It is an arithmetic number, because the mean of its divisors is an integer number (3325170690).

Almost surely, 213300452103 is an apocalyptic number.

13300452103 is a deficient number, since it is larger than the sum of its proper divisors (230657).

13300452103 is a wasteful number, since it uses less digits than its factorization.

13300452103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230656.

The product of its (nonzero) digits is 1080, while the sum is 22.

Adding to 13300452103 its reverse (30125400331), we get a palindrome (43425852434).

The spelling of 13300452103 in words is "thirteen billion, three hundred million, four hundred fifty-two thousand, one hundred three".

Divisors: 1 115019 115637 13300452103