1330050154117 has 2 divisors, whose sum is σ = 1330050154118. Its totient is φ = 1330050154116.

The previous prime is 1330050154099. The next prime is 1330050154127. The reversal of 1330050154117 is 7114510500331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1293847100676 + 36203053441 = 1137474^2 + 190271^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330050154117 - 2¹⁹ = 1330049629829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330050154127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665025077058 + 665025077059.

It is an arithmetic number, because the mean of its divisors is an integer number (665025077059).

Almost surely, 2^{1330050154117} is an apocalyptic number.

It is an amenable number.

1330050154117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330050154117 is an equidigital number, since it uses as much as digits as its factorization.

1330050154117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6300, while the sum is 31.

Adding to 1330050154117 its reverse (7114510500331), we get a palindrome (8444560654448).

The spelling of 1330050154117 in words is "one trillion, three hundred thirty billion, fifty million, one hundred fifty-four thousand, one hundred seventeen".