133005301431551 has 4 divisors (see below), whose sum is σ = 133058060379504. Its totient is φ = 132952542483600.

The previous prime is 133005301431533. The next prime is 133005301431649. The reversal of 133005301431551 is 155134103500331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133005301431551 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133005301431451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26379470195 + ... + 26379475236.

It is an arithmetic number, because the mean of its divisors is an integer number (33264515094876).

Almost surely, 2^{133005301431551} is an apocalyptic number.

133005301431551 is a deficient number, since it is larger than the sum of its proper divisors (52758947953).

133005301431551 is an equidigital number, since it uses as much as digits as its factorization.

133005301431551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52758947952.

The product of its (nonzero) digits is 40500, while the sum is 35.

Adding to 133005301431551 its reverse (155134103500331), we get a palindrome (288139404931882).

The spelling of 133005301431551 in words is "one hundred thirty-three trillion, five billion, three hundred one million, four hundred thirty-one thousand, five hundred fifty-one".