Base | Representation |
---|---|
bin | 11110001111011110110110… |
… | …100000100110101001010010 |
3 | 122102221011222000222201012120 |
4 | 132033132312200212221102 |
5 | 114413124340422133232 |
6 | 1150513444200235110 |
7 | 40005213451324626 |
oct | 3617366640465122 |
9 | 572834860881176 |
10 | 133005314255442 |
11 | 3941a267501752 |
12 | 12b013a276ba96 |
13 | 592a469093225 |
14 | 24bb6c4b9b186 |
15 | 1059b9061b92c |
hex | 78f7b6826a52 |
133005314255442 has 64 divisors (see below), whose sum is σ = 283711454841600. Its totient is φ = 41424092272640.
The previous prime is 133005314255441. The next prime is 133005314255449. The reversal of 133005314255442 is 244552413500331.
It is a junction number, because it is equal to n+sod(n) for n = 133005314255394 and 133005314255403.
It is not an unprimeable number, because it can be changed into a prime (133005314255441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 915342 + ... + 16335497.
It is an arithmetic number, because the mean of its divisors is an integer number (4432991481900).
Almost surely, 2133005314255442 is an apocalyptic number.
133005314255442 is an abundant number, since it is smaller than the sum of its proper divisors (150706140586158).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133005314255442 is a wasteful number, since it uses less digits than its factorization.
133005314255442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17251411.
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 133005314255442 its reverse (244552413500331), we get a palindrome (377557727755773).
The spelling of 133005314255442 in words is "one hundred thirty-three trillion, five billion, three hundred fourteen million, two hundred fifty-five thousand, four hundred forty-two".
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