Search a number
-
+
1330100113019 = 5087261470437
BaseRepresentation
bin10011010110110000001…
…001010000111001111011
311201011012222000121211212
4103112300021100321323
5133243021112104034
62455012313313335
7165045056263046
oct23266011207173
94634188017755
101330100113019
11473101924657
12195947a0584b
13985741425c2
144853d013c5d
15248eb7272ce
hex135b0250e7b

1330100113019 has 4 divisors (see below), whose sum is σ = 1330361588544. Its totient is φ = 1329838637496.

The previous prime is 1330100112977. The next prime is 1330100113021. The reversal of 1330100113019 is 9103110010331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330100113019 - 228 = 1329831677563 is a prime.

It is a super-2 number, since 2×13301001130192 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330100112985 and 1330100113003.

It is not an unprimeable number, because it can be changed into a prime (1330100113519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130730132 + ... + 130740305.

It is an arithmetic number, because the mean of its divisors is an integer number (332590397136).

Almost surely, 21330100113019 is an apocalyptic number.

1330100113019 is a deficient number, since it is larger than the sum of its proper divisors (261475525).

1330100113019 is an equidigital number, since it uses as much as digits as its factorization.

1330100113019 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261475524.

The product of its (nonzero) digits is 243, while the sum is 23.

The spelling of 1330100113019 in words is "one trillion, three hundred thirty billion, one hundred million, one hundred thirteen thousand, nineteen".

Divisors: 1 5087 261470437 1330100113019