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1330100314489 is a prime number
BaseRepresentation
bin10011010110110000001…
…010000010000101111001
311201011012222101212012201
4103112300022002011321
5133243021140030424
62455012321510201
7165045061062322
oct23266012020571
94634188355181
101330100314489
11473101a51a61
12195947aa2361
13985741b320b
144853d067449
15248eb766d44
hex135b0282179

1330100314489 has 2 divisors, whose sum is σ = 1330100314490. Its totient is φ = 1330100314488.

The previous prime is 1330100314369. The next prime is 1330100314531. The reversal of 1330100314489 is 9844130010331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1266374360889 + 63725953600 = 1125333^2 + 252440^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330100314489 - 217 = 1330100183417 is a prime.

It is a super-2 number, since 2×13301003144892 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1330100311489) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665050157244 + 665050157245.

It is an arithmetic number, because the mean of its divisors is an integer number (665050157245).

Almost surely, 21330100314489 is an apocalyptic number.

It is an amenable number.

1330100314489 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330100314489 is an equidigital number, since it uses as much as digits as its factorization.

1330100314489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 1330100314489 in words is "one trillion, three hundred thirty billion, one hundred million, three hundred fourteen thousand, four hundred eighty-nine".