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13301011023 = 3411036910429
BaseRepresentation
bin11000110001100110…
…10101001001001111
31021022222012100221220
430120303111021033
5204220024323043
610035502454423
7650416504536
oct143063251117
937288170856
1013301011023
11570608a4a3
1226b2594413
13133c864a31
1490272331d
1552cab0483
hex318cd524f

13301011023 has 16 divisors (see below), whose sum is σ = 18170728800. Its totient is φ = 8649400320.

The previous prime is 13301011019. The next prime is 13301011033. The reversal of 13301011023 is 32011010331.

13301011023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13301011023 - 22 = 13301011019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13301010993 and 13301011011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13301011013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1270173 + ... + 1280601.

It is an arithmetic number, because the mean of its divisors is an integer number (1135670550).

Almost surely, 213301011023 is an apocalyptic number.

13301011023 is a deficient number, since it is larger than the sum of its proper divisors (4869717777).

13301011023 is a wasteful number, since it uses less digits than its factorization.

13301011023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20842.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13301011023 its reverse (32011010331), we get a palindrome (45312021354).

The spelling of 13301011023 in words is "thirteen billion, three hundred one million, eleven thousand, twenty-three".

Divisors: 1 3 41 123 10369 10429 31107 31287 425129 427589 1275387 1282767 108138301 324414903 4433670341 13301011023