133010320111321 has 4 divisors (see below), whose sum is σ = 133043664392100. Its totient is φ = 132976975830544.

The previous prime is 133010320111301. The next prime is 133010320111327. The reversal of 133010320111321 is 123111023010331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 77424512774400 + 55585807336921 = 8799120^2 + 7455589^2 .

It is a cyclic number.

It is not a de Polignac number, because 133010320111321 - 2¹¹ = 133010320109273 is a prime.

It is a super-2 number, since 2×133010320111321² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133010320111292 and 133010320111301.

It is not an unprimeable number, because it can be changed into a prime (133010320111327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16672134406 + ... + 16672142383.

It is an arithmetic number, because the mean of its divisors is an integer number (33260916098025).

Almost surely, 2^{133010320111321} is an apocalyptic number.

It is an amenable number.

133010320111321 is a deficient number, since it is larger than the sum of its proper divisors (33344280779).

133010320111321 is an equidigital number, since it uses as much as digits as its factorization.

133010320111321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33344280778.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 133010320111321 its reverse (123111023010331), we get a palindrome (256121343121652).

The spelling of 133010320111321 in words is "one hundred thirty-three trillion, ten billion, three hundred twenty million, one hundred eleven thousand, three hundred twenty-one".