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1330103220037 is a prime number
BaseRepresentation
bin10011010110110000010…
…101000111011101000101
311201011020011212110212121
4103112300111013131011
5133243022411020122
62455012504045541
7165045124553314
oct23266025073505
94634204773777
101330103220037
11473103656a39
12195948a638b1
139857498c887
144853d5c227b
15248ebb3cbc7
hex135b0547745

1330103220037 has 2 divisors, whose sum is σ = 1330103220038. Its totient is φ = 1330103220036.

The previous prime is 1330103220001. The next prime is 1330103220071. The reversal of 1330103220037 is 7300223010331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1008757088161 + 321346131876 = 1004369^2 + 566874^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1330103220037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330103219993 and 1330103220020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330103220337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665051610018 + 665051610019.

It is an arithmetic number, because the mean of its divisors is an integer number (665051610019).

Almost surely, 21330103220037 is an apocalyptic number.

It is an amenable number.

1330103220037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330103220037 is an equidigital number, since it uses as much as digits as its factorization.

1330103220037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268, while the sum is 25.

Adding to 1330103220037 its reverse (7300223010331), we get a palindrome (8630326230368).

The spelling of 1330103220037 in words is "one trillion, three hundred thirty billion, one hundred three million, two hundred twenty thousand, thirty-seven".