Base | Representation |
---|---|
bin | 1100000110001110001101… |
… | …0110010101100011010001 |
3 | 1202002120021212021000100221 |
4 | 3001203203112111203101 |
5 | 3220411003424010024 |
6 | 44142224335113041 |
7 | 2541652666221601 |
oct | 301434326254321 |
9 | 52076255230327 |
10 | 13301033031889 |
11 | 4268a33431159 |
12 | 15a99b5072781 |
13 | 75638881b1a5 |
14 | 33dab8432c01 |
15 | 180ecc89e3e4 |
hex | c18e35958d1 |
13301033031889 has 2 divisors, whose sum is σ = 13301033031890. Its totient is φ = 13301033031888.
The previous prime is 13301033031877. The next prime is 13301033031901. The reversal of 13301033031889 is 98813033010331.
It is a balanced prime because it is at equal distance from previous prime (13301033031877) and next prime (13301033031901).
It can be written as a sum of positive squares in only one way, i.e., 8056855171600 + 5244177860289 = 2838460^2 + 2290017^2 .
It is a cyclic number.
It is not a de Polignac number, because 13301033031889 - 25 = 13301033031857 is a prime.
It is not a weakly prime, because it can be changed into another prime (13301033035889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650516515944 + 6650516515945.
It is an arithmetic number, because the mean of its divisors is an integer number (6650516515945).
Almost surely, 213301033031889 is an apocalyptic number.
It is an amenable number.
13301033031889 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301033031889 is an equidigital number, since it uses as much as digits as its factorization.
13301033031889 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 13301033031889 in words is "thirteen trillion, three hundred one billion, thirty-three million, thirty-one thousand, eight hundred eighty-nine".
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